Find the concentration of H+ ions at a pH = 11 and pH = 6. Then divide the concentration of H+ ions at a pH = 11 by the of H+ ions at a pH = 6. Record your answer in Table C. What is the concentration of H+ ions at a pH = 11? mol/L What is the concentration of H+ ions at a pH = 6? mol/L How many fewer H+ ions are there in a solution at a pH = 11 than in a solution at a pH = 6?
the hydrogen ion concentration can be calculated using pH pH = -log [H⁺] when pH is known antilog of pH needs to be calculated [H⁺] = antilog (-pH) when pH = 11 [H⁺] = antilog(-11) [H⁺] = 1 x 10⁻¹¹ mol/L
when pH = 6 [H⁺] = antilog (-6) [H⁺] = 1 x 10⁻⁶ mol/L
then to find how much fewer H⁺ ions at pH = 11 than when pH = 6, we have to find the ratio. ratio = (1 x 10⁻¹¹ mol/L) / (1 x 10⁻⁶ mol/L) there's 10⁻⁵ lesser H⁺ ions when pH - 11 than when pH - 6
