What is the largest of three consecutive positive integers if the sum of the smaller two integers is 11

Question

02-01-2017
Mathematics

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What is the largest of three consecutive positive integers if the sum of the smaller two integers is 11

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Аноним Аноним · Answer 1 · 2017-01-03T12:54:56+01:00

Аноним Аноним

03-01-2017

Let, the numbers are: x, (x+1), (x+2)
Now, x+x+1 = 11
2x + 1 = 11
2x = 10
x = 5

So, largest number would be: (x+2) = (5+2) = 7

In short, Your Final answer would be 7

Hope this helps!

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