MusicLover123
MusicLover123 MusicLover123
  • 03-06-2016
  • Mathematics
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I don't know what method I should use to solve for y in this equation: (y-3)^2=4y-12

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Tareki
Tareki Tareki
  • 03-06-2016
(y-3)^2 -4y +12 = 0 
[y^2 -6y +9] -4y +12 =0 
y^2 -10y + 21 = 0 
(y -3) (y-7) =0 
y=3 ; y = 7 
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