nataliesalinassander nataliesalinassander

01-08-2019
Mathematics

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samrinc samrinc

01-08-2019

base:
sin 32° / 3 = sin 58 ° / h
3 sin 58° = sin 32 ° h
3 sin 58 ° / sin 32 ° = h

(1/2)(3 sin 58° / sin 32°)(6) * 5
A = 15(3 sin 58° / sin 32°)

triangles
A = 5(1/2)(14)(6)
A = 210 sq in

total area
210 + 15(3 sin 58° / sin 32°) = approx. 282.02 sq in

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